11 lines
318 B
Python
11 lines
318 B
Python
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import re
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def extract_version_number(version):
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number = re.findall(r'[0-9]+\.?[0-9]?', version)
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if not number:
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raise ValueError("No version number matches for '%s'" % version)
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if len(number) > 1:
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raise ValueError("Multiple version number matches for '%s'" % version)
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return number[0]
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