Use venv from mod-apache
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@ -8,11 +8,13 @@ Define appdir /path/to/app/dir
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# The path where the app directory is. Apache must have access to this folder.
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Define wsgipath ${appdir}/wsgi.wsgi
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# The location of the .wsgi file
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Define pyvenv /path/to/venv
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# The path where the virtual environment is (the folder containing bin/activate)
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<VirtualHost *:80>
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ServerName ${servername}
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WSGIDaemonProcess "${servername}" threads=5 lang='en_US.UTF-8' locale='en_US.UTF-8'
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WSGIDaemonProcess "${servername}" threads=5 lang='en_US.UTF-8' locale='en_US.UTF-8' python-home="${pyvenv}"
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WSGIScriptAlias / ${wsgipath}
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# pass the required headers through to the application
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@ -3,7 +3,7 @@ An exemplifying Apache python WSGI to a Devicehub app.
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Based in http://flask.pocoo.org/docs/0.12/deploying/mod_wsgi/
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You only need to modify ``app_dir`` and ``venv``.
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You only need to modify ``app_dir``.
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"""
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from pathlib import Path
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@ -11,28 +11,13 @@ from pathlib import Path
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import sys
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app_dir = Path(__file__).parent
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"""
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The **directory** where app.py is located.
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Change this accordingly.
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"""
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"""The **directory** where app.py is located. Change this accordingly."""
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assert app_dir.is_dir(), 'app_dir must point to a directory: {}'.format(app_dir)
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app_dir = str(app_dir.resolve())
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venv = Path(__file__).parent.parent / 'venv' / 'bin' / 'activate_this.py'
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"""
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The location of the ``activate_this.py`` file of the virtualenv.
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Change this accordingly.
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"""
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assert venv.is_file(), 'venv must point to a file: {}'.format(venv)
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venv = str(venv.resolve())
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# Load the virtualenv
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# -------------------
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_globals = dict(__file__=venv)
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exec(open(venv).read(), _globals)
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# Load the app
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# ------------
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sys.path.insert(0, str(app_dir))
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# noinspection PyUnresolvedReferences
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from app import app as application
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from app import app as application
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